Integrand size = 22, antiderivative size = 146 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {5 b (7 A b-4 a B)}{8 a^4 \sqrt {a+b x^2}}-\frac {5 b (7 A b-4 a B) \text {arctanh}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{8 a^{9/2}} \]
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Time = 0.09 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {457, 79, 44, 53, 65, 214} \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=-\frac {5 b (7 A b-4 a B) \text {arctanh}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{8 a^{9/2}}+\frac {5 b (7 A b-4 a B)}{8 a^4 \sqrt {a+b x^2}}+\frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}} \]
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Rule 44
Rule 53
Rule 65
Rule 79
Rule 214
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {A+B x}{x^3 (a+b x)^{5/2}} \, dx,x,x^2\right ) \\ & = -\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {\left (-\frac {7 A b}{2}+2 a B\right ) \text {Subst}\left (\int \frac {1}{x^2 (a+b x)^{5/2}} \, dx,x,x^2\right )}{4 a} \\ & = -\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {(5 b (7 A b-4 a B)) \text {Subst}\left (\int \frac {1}{x (a+b x)^{5/2}} \, dx,x,x^2\right )}{16 a^2} \\ & = \frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {(5 b (7 A b-4 a B)) \text {Subst}\left (\int \frac {1}{x (a+b x)^{3/2}} \, dx,x,x^2\right )}{16 a^3} \\ & = \frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {5 b (7 A b-4 a B)}{8 a^4 \sqrt {a+b x^2}}+\frac {(5 b (7 A b-4 a B)) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^2\right )}{16 a^4} \\ & = \frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {5 b (7 A b-4 a B)}{8 a^4 \sqrt {a+b x^2}}+\frac {(5 (7 A b-4 a B)) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^2}\right )}{8 a^4} \\ & = \frac {5 b (7 A b-4 a B)}{24 a^3 \left (a+b x^2\right )^{3/2}}-\frac {A}{4 a x^4 \left (a+b x^2\right )^{3/2}}+\frac {7 A b-4 a B}{8 a^2 x^2 \left (a+b x^2\right )^{3/2}}+\frac {5 b (7 A b-4 a B)}{8 a^4 \sqrt {a+b x^2}}-\frac {5 b (7 A b-4 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{8 a^{9/2}} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.82 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\frac {105 A b^3 x^6+a^2 b x^2 \left (21 A-80 B x^2\right )+20 a b^2 x^4 \left (7 A-3 B x^2\right )-6 a^3 \left (A+2 B x^2\right )}{24 a^4 x^4 \left (a+b x^2\right )^{3/2}}+\frac {5 b (-7 A b+4 a B) \text {arctanh}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{8 a^{9/2}} \]
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Time = 2.96 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.81
method | result | size |
pseudoelliptic | \(\frac {-\frac {35 x^{4} \left (A b -\frac {4 B a}{7}\right ) \left (b \,x^{2}+a \right )^{\frac {3}{2}} b \,\operatorname {arctanh}\left (\frac {\sqrt {b \,x^{2}+a}}{\sqrt {a}}\right )}{8}+\frac {35 x^{4} \left (-\frac {3 x^{2} B}{7}+A \right ) b^{2} a^{\frac {3}{2}}}{6}+\frac {7 b \,x^{2} \left (-\frac {80 x^{2} B}{21}+A \right ) a^{\frac {5}{2}}}{8}+\frac {\left (-2 x^{2} B -A \right ) a^{\frac {7}{2}}}{4}+\frac {35 A \sqrt {a}\, b^{3} x^{6}}{8}}{a^{\frac {9}{2}} x^{4} \left (b \,x^{2}+a \right )^{\frac {3}{2}}}\) | \(118\) |
default | \(B \left (-\frac {1}{2 a \,x^{2} \left (b \,x^{2}+a \right )^{\frac {3}{2}}}-\frac {5 b \left (\frac {1}{3 a \left (b \,x^{2}+a \right )^{\frac {3}{2}}}+\frac {\frac {1}{a \sqrt {b \,x^{2}+a}}-\frac {\ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )}{a^{\frac {3}{2}}}}{a}\right )}{2 a}\right )+A \left (-\frac {1}{4 a \,x^{4} \left (b \,x^{2}+a \right )^{\frac {3}{2}}}-\frac {7 b \left (-\frac {1}{2 a \,x^{2} \left (b \,x^{2}+a \right )^{\frac {3}{2}}}-\frac {5 b \left (\frac {1}{3 a \left (b \,x^{2}+a \right )^{\frac {3}{2}}}+\frac {\frac {1}{a \sqrt {b \,x^{2}+a}}-\frac {\ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )}{a^{\frac {3}{2}}}}{a}\right )}{2 a}\right )}{4 a}\right )\) | \(200\) |
risch | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (-11 A b \,x^{2}+4 B a \,x^{2}+2 A a \right )}{8 a^{4} x^{4}}-\frac {35 b^{2} \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right ) A}{8 a^{\frac {9}{2}}}+\frac {5 b \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right ) B}{2 a^{\frac {7}{2}}}-\frac {19 b^{2} \sqrt {\left (x +\frac {\sqrt {-a b}}{b}\right )^{2} b -2 \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}\, A}{12 a^{4} \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}+\frac {13 b \sqrt {\left (x +\frac {\sqrt {-a b}}{b}\right )^{2} b -2 \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}\, B}{12 a^{3} \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}+\frac {19 b^{2} \sqrt {\left (x -\frac {\sqrt {-a b}}{b}\right )^{2} b +2 \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}\, A}{12 a^{4} \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}-\frac {13 b \sqrt {\left (x -\frac {\sqrt {-a b}}{b}\right )^{2} b +2 \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}\, B}{12 a^{3} \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}-\frac {b \sqrt {\left (x -\frac {\sqrt {-a b}}{b}\right )^{2} b +2 \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}\, A}{12 a^{4} \left (x -\frac {\sqrt {-a b}}{b}\right )^{2}}+\frac {\sqrt {\left (x -\frac {\sqrt {-a b}}{b}\right )^{2} b +2 \sqrt {-a b}\, \left (x -\frac {\sqrt {-a b}}{b}\right )}\, B}{12 a^{3} \left (x -\frac {\sqrt {-a b}}{b}\right )^{2}}-\frac {b \sqrt {\left (x +\frac {\sqrt {-a b}}{b}\right )^{2} b -2 \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}\, A}{12 a^{4} \left (x +\frac {\sqrt {-a b}}{b}\right )^{2}}+\frac {\sqrt {\left (x +\frac {\sqrt {-a b}}{b}\right )^{2} b -2 \sqrt {-a b}\, \left (x +\frac {\sqrt {-a b}}{b}\right )}\, B}{12 a^{3} \left (x +\frac {\sqrt {-a b}}{b}\right )^{2}}\) | \(618\) |
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Time = 0.28 (sec) , antiderivative size = 407, normalized size of antiderivative = 2.79 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\left [-\frac {15 \, {\left ({\left (4 \, B a b^{3} - 7 \, A b^{4}\right )} x^{8} + 2 \, {\left (4 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{6} + {\left (4 \, B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{4}\right )} \sqrt {a} \log \left (-\frac {b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) + 2 \, {\left (15 \, {\left (4 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{6} + 6 \, A a^{4} + 20 \, {\left (4 \, B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{4} + 3 \, {\left (4 \, B a^{4} - 7 \, A a^{3} b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{48 \, {\left (a^{5} b^{2} x^{8} + 2 \, a^{6} b x^{6} + a^{7} x^{4}\right )}}, -\frac {15 \, {\left ({\left (4 \, B a b^{3} - 7 \, A b^{4}\right )} x^{8} + 2 \, {\left (4 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{6} + {\left (4 \, B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{4}\right )} \sqrt {-a} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) + {\left (15 \, {\left (4 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{6} + 6 \, A a^{4} + 20 \, {\left (4 \, B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{4} + 3 \, {\left (4 \, B a^{4} - 7 \, A a^{3} b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{24 \, {\left (a^{5} b^{2} x^{8} + 2 \, a^{6} b x^{6} + a^{7} x^{4}\right )}}\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 1323 vs. \(2 (141) = 282\).
Time = 44.24 (sec) , antiderivative size = 1323, normalized size of antiderivative = 9.06 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\text {Too large to display} \]
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Time = 0.21 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.12 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\frac {5 \, B b \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{2 \, a^{\frac {7}{2}}} - \frac {35 \, A b^{2} \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{8 \, a^{\frac {9}{2}}} - \frac {5 \, B b}{2 \, \sqrt {b x^{2} + a} a^{3}} - \frac {5 \, B b}{6 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{2}} + \frac {35 \, A b^{2}}{8 \, \sqrt {b x^{2} + a} a^{4}} + \frac {35 \, A b^{2}}{24 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{3}} - \frac {B}{2 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a x^{2}} + \frac {7 \, A b}{8 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{2} x^{2}} - \frac {A}{4 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a x^{4}} \]
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Time = 0.30 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.13 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=-\frac {5 \, {\left (4 \, B a b - 7 \, A b^{2}\right )} \arctan \left (\frac {\sqrt {b x^{2} + a}}{\sqrt {-a}}\right )}{8 \, \sqrt {-a} a^{4}} - \frac {6 \, {\left (b x^{2} + a\right )} B a b + B a^{2} b - 9 \, {\left (b x^{2} + a\right )} A b^{2} - A a b^{2}}{3 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{4}} - \frac {4 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} B a b - 4 \, \sqrt {b x^{2} + a} B a^{2} b - 11 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} A b^{2} + 13 \, \sqrt {b x^{2} + a} A a b^{2}}{8 \, a^{4} b^{2} x^{4}} \]
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Time = 6.32 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.21 \[ \int \frac {A+B x^2}{x^5 \left (a+b x^2\right )^{5/2}} \, dx=\frac {35\,A\,b^2}{6\,a^3\,{\left (b\,x^2+a\right )}^{3/2}}-\frac {10\,B\,b}{3\,a^2\,{\left (b\,x^2+a\right )}^{3/2}}-\frac {35\,A\,b^2\,\mathrm {atanh}\left (\frac {\sqrt {b\,x^2+a}}{\sqrt {a}}\right )}{8\,a^{9/2}}-\frac {A}{4\,a\,x^4\,{\left (b\,x^2+a\right )}^{3/2}}-\frac {B}{2\,a\,x^2\,{\left (b\,x^2+a\right )}^{3/2}}+\frac {5\,B\,b\,\mathrm {atanh}\left (\frac {\sqrt {b\,x^2+a}}{\sqrt {a}}\right )}{2\,a^{7/2}}+\frac {7\,A\,b}{8\,a^2\,x^2\,{\left (b\,x^2+a\right )}^{3/2}}+\frac {35\,A\,b^3\,x^2}{8\,a^4\,{\left (b\,x^2+a\right )}^{3/2}}-\frac {5\,B\,b^2\,x^2}{2\,a^3\,{\left (b\,x^2+a\right )}^{3/2}} \]
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